Test Prep GMAT Test Exam Practice Questions (P. 5)
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Question #41
George can fill Q cans of paint in 3 minutes. If there are R cans of paint in one gallon, how many gallons can George fill in 45 minutes?
- A30R/Q
- B15R/Q
- C30Q/R
- D5Q/R
- E15Q/R
Correct Answer:
E
George can fill Q/3 cans of paint in one minute. There are R cans in one gallon, so R / (Q/3) = 3R/Q is the time it takes George to fill one gallon (in minutes). In 45 minutes George can fill up 45 / (3R/Q) = 15Q/R.
E
George can fill Q/3 cans of paint in one minute. There are R cans in one gallon, so R / (Q/3) = 3R/Q is the time it takes George to fill one gallon (in minutes). In 45 minutes George can fill up 45 / (3R/Q) = 15Q/R.
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Question #42
If (4 # 2 = 14) and (2 # 3 = 6), what can replace (a # b)?
- Aab
- B(a + 3) b
- Ca גˆ’ b.
- Da גˆ’ 2. b
- Eb + 1. a
Correct Answer:
D
Plug in the answers.
A. (4 # 2) = 4 ֳ— 2 = 8. The answer should be 14.
B. (2 # 3) = (2 + 3)
= 15. The answer should be 6.
C. (2 # 3) = (2 -
גˆ’ 3) = 1. The answer should be 6.
D. (4 # 2) = (4 -
גˆ’ 2) = 14. This is the right answer; check (2 # 3) also.
D
Plug in the answers.
A. (4 # 2) = 4 ֳ— 2 = 8. The answer should be 14.
B. (2 # 3) = (2 + 3)
= 15. The answer should be 6.
C. (2 # 3) = (2 -
גˆ’ 3) = 1. The answer should be 6.
D. (4 # 2) = (4 -
גˆ’ 2) = 14. This is the right answer; check (2 # 3) also.
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Question #43
In a rectangular coordinate system, what is the square root of the area of a trapezoid whose vertices have the coordinates (2, גˆ’2), (2, 3), (20, 2), (20, גˆ’2)?
- A7.5
- B9
- C10.22
- D12.25
- E14
Correct Answer:
B
Draw the x- and y-axes, then plot the points and connect them.
The area of a trapezoid is (base
+ base
) ֳ— (height) / 2.
Base -
= 5, base
= 4, height = 18 thus the area is 9 ֳ— 9 = 81.
The answer to the question is the square root of 81, meaning 9.
B
Draw the x- and y-axes, then plot the points and connect them.
The area of a trapezoid is (base
+ base
) ֳ— (height) / 2.
Base -
= 5, base
= 4, height = 18 thus the area is 9 ֳ— 9 = 81.
The answer to the question is the square root of 81, meaning 9.
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Question #44
If the least common multiple of two prime numbers x and y is 10, where x > y, then the value of 2x + y is
- A7
- B9
- C11
- D12
- E21
Correct Answer:
D
The only prime numbers that satisfy this condition are 2 and 5. Since x > y, x = 5 and y = 2. Therefore, by substitution, 2(5) + 2 = 10 + 2 = 12.
D
The only prime numbers that satisfy this condition are 2 and 5. Since x > y, x = 5 and y = 2. Therefore, by substitution, 2(5) + 2 = 10 + 2 = 12.
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Question #45
What is the product of 6% and 14%?
- A0.00084
- B0.0084
- C0.084
- D0.84
- E8.4
Correct Answer:
B
Convert 6% to its decimal equivalent of 0.06 and 14% to 0.14. The key word ג€productג€ tell you to multiply, so 0.06 ֳ— 0.14 = 0.0084.
B
Convert 6% to its decimal equivalent of 0.06 and 14% to 0.14. The key word ג€productג€ tell you to multiply, so 0.06 ֳ— 0.14 = 0.0084.
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Question #46
A taxicab fare costs x dollars for the first quarter of a mile and (
/
)x dollars for each quarter of a mile after that. How much will the total cost be for a 2
/
mile ride?
/
)x dollars for each quarter of a mile after that. How much will the total cost be for a 2
/
mile ride?
- A3x
- B( / )x
- C10x
- D( / )x
- E2.5x
Correct Answer:
B
/
miles divided by 1/4 is ten quarter miles. Since the first quarter mile costs x amount, the other nine quarter miles cost (
/
)x, so 9 ֳ— (
/
)x = (
/
)x.
x + (
/
)x = (
/
)x + (
/
)x = (
/
)x.
B
/
miles divided by 1/4 is ten quarter miles. Since the first quarter mile costs x amount, the other nine quarter miles cost (
/
)x, so 9 ֳ— (
/
)x = (
/
)x.
x + (
/
)x = (
/
)x + (
/
)x = (
/
)x.
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Question #47
Which of the following measures could form the sides of a triangle?
I) 3, 3, 5 -
II) 6, 6, 12 -
III) 1, 2, 3 -
I) 3, 3, 5 -
II) 6, 6, 12 -
III) 1, 2, 3 -
- AI only
- BII only
- CIII only
- DI and II only
- EII and III only
Correct Answer:
A
The sum of the measures of the two shorter sides of a triangle must be greater than the longest side. Since 3 + 3 > 5, statement I works. Since 6 + 6 = 12 and 1 +
2 = 3, they do not form the sides of the triangle. The answer is statement I only.
A
The sum of the measures of the two shorter sides of a triangle must be greater than the longest side. Since 3 + 3 > 5, statement I works. Since 6 + 6 = 12 and 1 +
2 = 3, they do not form the sides of the triangle. The answer is statement I only.
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Question #48
Scott's average (arithmetic mean) golf score on his first four rounds was 78. What score does he need on his fifth round to drop his average score by 2 points?
- A68
- B72
- C78
- D88
- E312
Correct Answer:
A
If the average of four rounds is 78, then the total points scored is 78 ֳ— 4 = 312. If his score were to drop 2 points that means his new average would be 76. A 76 average for five rounds is a total of 380 points. The difference between these two point totals is 380 גˆ’ 312 = 68. He needs a score of 68 on the fifth round.
A
If the average of four rounds is 78, then the total points scored is 78 ֳ— 4 = 312. If his score were to drop 2 points that means his new average would be 76. A 76 average for five rounds is a total of 380 points. The difference between these two point totals is 380 גˆ’ 312 = 68. He needs a score of 68 on the fifth round.
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Question #49
Celeste worked for h hours each day for d consecutive days. If she earns $9.50 per hour, what is the total amount she earned?
- A9.50 / (d + h)
- B9.50 + d + h
- C9.50 + dh
- D9.50h + d
- E9.50dh
Correct Answer:
E
Suppose Celeste worked for 8 hours each day for 5 consecutive days. Her total pay would be found by finding her total hours (8 ֳ— 5 = 40) and then multiplying 40 by her pay per hour ($9.50). Since you are only multiplying to solve the problem, the expression is 9.50 ֳ— d ֳ— h or 9.50dh.
E
Suppose Celeste worked for 8 hours each day for 5 consecutive days. Her total pay would be found by finding her total hours (8 ֳ— 5 = 40) and then multiplying 40 by her pay per hour ($9.50). Since you are only multiplying to solve the problem, the expression is 9.50 ֳ— d ֳ— h or 9.50dh.
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Question #50
A certain jacket was marked down 20% the first week and another 20% the next week. What percent of the regular price was the final cost of the jacket after the two markdowns?
- A30%
- B36%
- C40%
- D60%
- E64%
Correct Answer:
E
To make this problem easier, assume the initial cost of the jacket was $100. The first markdown of 20% would save you $20, bringing the cost of the jacket to $80.
For the second markdown, you should be finding 20% of $80, the new cost of the jacket. 20% of 80 = 0.20 ֳ— 80 = 16. If you save $16 the second time, the final cost of the jacket is 80 גˆ’ 16 = $64. Since the initial cost was $100, $64 is 64% of this price.
E
To make this problem easier, assume the initial cost of the jacket was $100. The first markdown of 20% would save you $20, bringing the cost of the jacket to $80.
For the second markdown, you should be finding 20% of $80, the new cost of the jacket. 20% of 80 = 0.20 ֳ— 80 = 16. If you save $16 the second time, the final cost of the jacket is 80 גˆ’ 16 = $64. Since the initial cost was $100, $64 is 64% of this price.
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