Test Prep GRE Section 2 Quantitative Exam Practice Questions (P. 1)
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Question #1

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
C
To determine Quantity A, substitute the number 2 for a and for b in the centered equation:
(2 + 2)(22 2) = (4)(0) = 0
Follow the same procedure for the quantity in Column B:

The quantities in both columns equal zero (0).

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Question #2

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
A
For any fractional number between zero (0) and 1, the number is less than its square root, which in turn is less than its cube root.

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Question #3

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
A
A circles circumference is d the product of (a bit greater than 3.1) and the circles diameter. If AB and CD were each as large as possible, they would each equal the circles diameter. Three times this length is still be less than d.

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Question #4

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
D
Without knowing either interest rate, it is impossible to compute either quantity in order to make the comparison.

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Question #5

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
C
There are 2 prime numbers between 10 and 15: 11 and 13. The integer 33 has 2 prime factors: 3 and 11.

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Question #6

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
A
Given n= 2, the 25th term of Set R = 25n+ 25 = 25(2) + 25 = 75. Given n= 2, the 24th term of Set S =n+ 23 = 2 + 23 = 25, and two times that 24th term is 50.

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Question #7

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
C
Theres no need to calculate either quantity, and you can cancel the products from both columns. To make the comparison, observe the place-value shifts from the decimal number 9.3. In Column A, the decimal point shifts 3 places left (9,300) and 3 places right (.0093), so the quantity is equivalent to (9.3) (9.3). You can now see that Quantity B, which is (9.3)(9.3), is the same as Quantity A.

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Question #8

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
B
Theres no need to calculate either quantity. Given an area of 12,000 square feet, the shortest possible rectangular perimeter is achieved with a square, in which all sides are the same length. Column B describes a corral with a width of 300 feet and a length of 400 feet. This corral would require more fence posts than a square corral.

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Question #9

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
B
You can make the comparison quickly by recognizing that Quantity A is the

"difference of two squares" (
) in the factored form (x + y) (x -y), where y= 2. Or, you can multiply the two binomials in Column A, and then simplify:

Quantity A <Quantity B.

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Question #10

- AThe quantity in Column A is greater;
- BThe quantity in Column B is greater;
- CThe quantities are equal;
- DThe relationship cannot be determined from the information given.
A
Q percent is based on $100. Therefore, Q percent = Q dollars, and Quantity B will always be $1 less than Quantity A.

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